How do you evaluate #-32^(1/3) - 4^(1/3)#?

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Answer 1 · 2017-08-04T05:11:53

See a solution process below:

First, we can rewrite the expression as:

#(8 * -4)^(1/3) - 4^(1/3) =>#

#(8^(1/3) * -4^(1/3)) - 4^(1/3) =>#

#(2 * -4^(1/3)) - 4^(1/3) =>#

#(2 * -4^(1/3)) + (1 * -4^(1/3))#

Now, we can factor out the common term (#-4^(1/3)#) and add the remaining terms:

#(2 + 1)-4^(1/3)#

#3 * -4^(1/3)#