How do you evaluate #(3r + 2) ( 2r + 5)#?

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Answer 1 · 2017-08-01T13:37:47

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3r) + color(red)(2))(color(blue)(2r) + color(blue)(5))# becomes:

#(color(red)(3r) xx color(blue)(2r)) + (color(red)(3r) xx color(blue)(5)) + (color(red)(2) xx color(blue)(2r)) + (color(red)(2) xx color(blue)(5))#

#6r^2 + 15r + 4r + 10#

We can now combine like terms:

#6r^2 + (15 + 4)r + 10#

#6r^2 + 19r + 10#