How do you evaluate #3x^2-4y+xz# for #x=4, y=-5# and #z=2#?
1 Answer
Oct 7, 2017
Explanation:
#"substitute the given values for x, y and z into the"#
#"expression and evaluate"#
#rArr(3xx4^2)-(4xx-5)+(4xx2)#
#=(3xx16)-(-20)+8#
#=48+20+8#
#=76#
