How do you evaluate #4.2 times 8.1#?

1 Answer
Jan 27, 2017

#34.02#

Explanation:

#color(brown)("This is one method of several")#

Don't like decimals so lets get rid of them.

Write #4.2" as "42xx1/10#
Write #8.1" as "81xx1/10#

So #4.2xx8.1" "=" "42xx81xx1/10xx1/10#

But #1/10xx1/10=1/100#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Doing the calculation by splitting the 42 into 40 and 2")_#

#40xx81=3240#
#color(white)(4)2xx81=ul(color(white)(3)162) larr " add"#
#color(white)("ddddddddd")3402#

Now we apply the #xx1/100# giving

#3402xx1/100 = 34.02#