How do you evaluate #(4+ 8i ) - ( 3+ 3i )#?

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Answer 1 · 2017-12-06T03:34:58

#i=-1/5#

Transform the equation to an addition equation could make things easier

#(4+8i)-(3+3i)#

#(4+8i)+(-3-3i)#

I’m going to rearrange them to make things even easier.

#8i-3i+4-3#

#5i+1#

Now you want to solve to find i (You want to isolate it.)

#5i+1-1=0-1#

#5i=-1#

#(5i)/5= -1/5 #

#i=-1/5#