# How do you evaluate 4 radical 3 - radical 12?

Jan 4, 2016

$4 \sqrt{3} - \sqrt{12} = 2 \sqrt{3}$

#### Explanation:

If $a , b \ge 0$ then $\sqrt{a b} = \sqrt{a} \sqrt{b}$

So:

$4 \sqrt{3} - \sqrt{12}$

$= 4 \sqrt{3} - \sqrt{4 \cdot 3}$

$= 4 \sqrt{3} - \sqrt{4} \sqrt{3}$

$= 4 \sqrt{3} - 2 \sqrt{3} = 2 \sqrt{3}$