How do you evaluate #(4a + 7) ( 3a - 4)#?

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Answer 1 · 2017-11-30T20:22:13

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4a) + color(red)(7))(color(blue)(3a) - color(blue)(4))# becomes:

#(color(red)(4a) xx color(blue)(3a)) - (color(red)(4a) xx color(blue)(4)) + (color(red)(7) xx color(blue)(3a)) - (color(red)(7) xx color(blue)(4))#

#12a^2 - 16a + 21a - 28#

We can now combine like terms:

#12a^2 + (-16 + 21)a - 28#

#12a^2 + 5a - 28#