How do you evaluate #4i ^ { 5} - 2i ^ { 10} ( 3- \sqrt { - 4} )#?

1 Answer
SCooke
Dec 4, 2017

The "i" terms just depend on the multiple of the exponent. Pairs of "even" = 1, "odds" are the same as "i".

Explanation:

#4i^5 - 2i^10 xx (3 - sqrt(-4)#
#4i - 2(-1) xx (3 - sqrt(-4)#
#4i + 2 xx (3 - sqrt(-4)#
#4i + 6 - 2sqrt(-4)#
#4i + 6 - 2sqrt(4)i#
#4i + 6 - 2(2)i# ; #4i + 6 - 4i = 6#

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