How do you evaluate #-5n ^ { 2} \cdot 4n ^ { - 2}#?
1 Answer
Sep 16, 2017
Explanation:
#"using the "color(blue)"laws of exponents"#
#•color(white)(x)a^mxxa^n=a^((m+n))" and "a^0=1#
#rArr-5n^2 .4n^(-2)#
#=-5xxn^2xx4xxn^(-2)#
#=(-5xx4)xxn^2xxn^(-2)#
#=-20xxn^0#
#=-20xx1=-20#
