# How do you evaluate #5r-8.35s# when #r=12# and #s=4#?

##### 3 Answers

Jul 6, 2018

#### Answer:

#### Explanation:

Jul 6, 2018

#### Answer:

#### Explanation:

#"substitute the given values for r and s into the expression"#

#(5xxcolor(red)(12))-(8.35xxcolor(blue)(4))#

#=60-33.4#

#=26.6#

Jul 6, 2018

#### Answer:

#### Explanation:

We can just plug the values for the variables in our expression to get:

Hope this helps!