How do you evaluate #-6( - 3y ^ { 2} - 1+ 3u ^ { 3} )#?
1 Answer
Oct 3, 2017
Explanation:
#"simplify by distributing the bracket"#
#"that is multiply each term in the bracket by "-6#
#rArrcolor(red)(-6)(-3y^2-1+3u^3)#
#=(color(red)(-6)xx-3y^2)+(color(red)(-6)xx-1)+(color(red)(-6)xx3u^3)#
#=18y^2+6-18u^3#