How do you evaluate #(-6-4i)(-1+4i)#?

Question

1044 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-08T15:09:49

the answer is #2(11-10i)#

we have to multiply the given expression on multiplying we get
#6-24i+4i+16rArr22-20irArr2(11-10i)#

Answer 2 · 2017-11-08T15:10:30

#2(11-10i)#

#(-6-4i)(-1+4i)#
F - #-6*-1=6#
O - #-6*4i=-24i#
I - #-4i*-1=4i#
L - #-4i*4i=-16*-1=16#

#6-24i+4i+16=22-20i=2(11-10i)#