Question

How do you evaluate `6+ 81\div 1+ [ 9+ 7- 2] - 6`?

Answer 1

`6+81÷1+[9+7−2]−6=95`

Explanation:

`6+81÷1+[9+7−2]−6=6+81+[14]-6=cancel6+81+[14]-cancel6=81+14=95`

Answer 2

`95`

Explanation:

This is a classic question involving the order of operations, the order in which you must do operations. You can remember the order with the acronym BIDMAS:

`B`rackets;
`I`ndices (powers and roots);
`D`ivision or
`M`ultiplication;
`A`ddition or
`S`ubtraction

Multiplication and division; and addition and subtraction take the same precedence in this list. If there are more than one operations of the same precedence, eg two brackets or a multiplication and division, you work from left to right.

Taking our sum:

`6+81/1+(9+7-2)-6`

Begin with the brackets:

`6+81/1+14-6`

Then the division:

`6+81+14-6`

Then add up the answer to get

`95`

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That is, me assuming that it is only the 1 being divided into 81, which is how the question reads to me. If it was, for example, `81/(1+(9+7-2))`, you would evaluate the denominator first, `81/15` then work from here. I don't believe this is the case for the question, however; the answer is 95.