How do you evaluate #(6\cdot 4^ { 2} ) ^ { 3}#?

1 Answer
Nov 13, 2017

See a solution process below:

Explanation:

First, using the standard order for operations or PEDMAS, we first need to evaluate the inner exponent:

#(6 * color(red)(4^2))^3 => (6 * 16)^3#

Next, we evaluate the term within the parenthesis:

#(color(red)(6) * color(red)(16))^3 => (96)^3#

Now, we evaluate the final exponent:

#96^3 = 884736#