How do you evaluate #-6\frac { 3} { 5} \div - 3#?

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Answer 1 · 2018-05-18T02:51:09

evaluate the expression as the division of two fractions

# - 6 3/5 = - 33/5# an improper negative fraction.

# - 3 = -3/1 # an improper negative fraction.

Set this up as the division of two fractions

# (-33/5)/(-3/1)#

Multiply both the top and the bottom fractions by the inverse of the bottom fraction. A fraction multiplied by its inverse equals one.

#{(-33/5) xx (-1/3)}/{(-3/1) xx( -1 /3)}#

This results in

# ( -33/5 xx -1/3)#

a negative times a negative is a positive and #33/3 = 11# so
the result is

# -cancel33^11/5 xx -1/cancel3 = + 11/5#

# 11/5 = 2 1/5#

Answer 2 · 2018-05-18T06:35:42

#2 1/5#

To divide or multiply with fractions you need to change mixed numbers into improper fractions first.

#" "-6 3/5 div -3#

#= -33/5 div -3/1#

#= -cancel33^11/5 xx -1/cancel3" "larr# multiply by the reciprocal

#=+ 11/5" "larr# negative divided by negative gives a positive

#= 2 1/5" "larr# answer in the same form as the question