How do you evaluate #-6+ \frac { 8} { x } + 3f# if #x=4# and #f=7#?

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Answer 1 · 2017-07-15T14:43:28

See a solution process below:

To evaluate this expression substitute:

#color(red)(4)# for #color(red)(x)#

#color(blue)(7)# for #color(blue)(f)#

And calculate the result:

#-6 + 8/color(red)(x) + 3color(blue)(f)# becomes:

#-6 + 8/color(red)(4) + (3 * color(blue)(7)) =>#

#-6 + 2 + 21 =>#

#-6 + 23 =>#

#17#