How do you evaluate (6+ \sqrt { 7} ) ( 4- \sqrt { 7} )(6+7)(47)?

1 Answer
Sep 18, 2017

You can use the F.O.I.L. method but that only applies to binomials (such as these). A more general method is to write each term of the first factor as a multiplier of the second factor.

Explanation:

Write each term of the first factor as a multiplier of the second factor:

(6+ sqrt7) (4-sqrt 7) = 6(4-sqrt7) + sqrt7(4-sqrt7)(6+7)(47)=6(47)+7(47)

Use the distributive property on both terms of the right side:

(6+ sqrt7) (4-sqrt 7) = 24-6sqrt7 + 4sqrt7-sqrt7sqrt7(6+7)(47)=2467+4777

The last term becomes -7:

(6+ sqrt7) (4-sqrt 7) = 24-6sqrt7 + 4sqrt7-7(6+7)(47)=2467+477

Combine like terms:

(6+ sqrt7) (4-sqrt 7) = 17-2sqrt7(6+7)(47)=1727