How do you evaluate #6\times 2+[-3-2]#?

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Answer 1 · 2017-12-07T12:38:29

See a solution process below:

First, using the standard order of operation or PEDMAS, execute the subtract operation within the brackets or Parenthesis:

#6 xx 2 + [color(red)(-3) - color(red)(2)] =>#

#6 xx 2 + [-5] =>#

#6 xx 2 - 5#

Next execute the Multiplication operation:

#color(red)(6) xx color(red)(2) - 5 =>#

#12 - 5#

Now, execute the Subtraction operation:

#color(red)(12) - color(red)(5) =>#

#7#