How do you evaluate #(6v + 3) ( 6v - 1)#?

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Answer 1 · 2017-12-07T14:32:58

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(6v) + color(red)(3))(color(blue)(6v) - color(blue)(1))# becomes:

#(color(red)(6v) xx color(blue)(6v)) - (color(red)(6v) xx color(blue)(1)) + (color(red)(3) xx color(blue)(6v)) - (color(red)(3) xx color(blue)(1))#

#36v^2 - 6v + 18v - 3#

We can now combine like terms:

#36v^2 + (-6 + 18)v - 3#

#36v^2 + 12v - 3#