Question

How do you evaluate `(7!)/(4!)`?

Answer 1

210

Explanation:

Since
`n! =n(n-1)(n-2)...3*2*1`,

you get
`7! =7*6*5*4*3*2*1`

and
`4! =4*3*2*1`

Then

`(7!)/(4! )=(7*6*5*cancel(4*3*2*1)) /cancel (4*3*2*1)=210`