# How do you evaluate 7+(-4x^2) for x=0?

Jun 19, 2017

7

#### Explanation:

$7 + \left(- 4 {x}^{2}\right)$ for $x = 0$

Solution
Since $x = 0$ you have to substitute $0$ to anywhere you see $x$

$\therefore$ $7 + \left(- 4 \left({0}^{2}\right)\right)$

$7 + \left(- 4 \left(0\right)\right)$

$7 + \left(- 0\right)$

$7 - 0$

$A n s w e r$ $\to$ $7$

Jun 19, 2017

#### Explanation:

All you have to do is simply substitute 0 in for x:
$7 + \left(- 4 \left({0}^{2}\right)\right)$
$7 + \left(- 4 \left(0\right)\right)$
$7 + 0 = 7$