How do you evaluate #-7+ \log _ { 3} ( 5x ) = - 6#?

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Answer 1 · 2017-08-03T19:28:41

#-7+ \log _ { 3} ( 5x ) = - 6#

#\log _ { 3} ( 5x ) = 1#

#5x =3^1#

#5x =3#

Hence, #x =3/5#

1) Adding 7 to both sides.

2) Taking exponential them for base #x=3#.

3) Dividing them by 5 for solving #x#.