How do you evaluate #7+ t \leq 2( t + 3) +#2?

1 Answer
Sep 17, 2017

#t>=-1#

Explanation:

#7 + t<= 2(t+3)+2#
#t+7 <= 2t + 6 + 2#
#t+7<=2t + 8#
Combine like terms
#t - 2t <= 8-7#
#-t <= 1#
Divide both sides by -1
#(-t)/-1 <= (-1)/-1#
#t>=-1#

Just in case you would like to know how to graph the solution....here it is
graph{x>=-1 [-10, 10, -5, 5]}