How do you evaluate [(7×8)(15×4)]3]?

1 Answer
Oct 20, 2017

4

Explanation:

Let's take a look at this

[(7×8)(15×4)]

We'll go through the "order of operations" (PEMDAS), starting with parentheses.

[j(7×8)(15×4)j]

7×8 simplifies to 56

15×4 simplifies to 60

So, we have [j(56)(60)j]

56(60) is the same as 56+60, which is 4

So, now we are left with
[j4j] or just 4