How do you evaluate #(8+ 2) \times ( 13- 3)#?

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Answer 1 · 2017-11-18T06:39:29

Simplify and then evaluate normally.

Because there are only integers in the brackets, we can simplify each bracket and then multiply the two terms.

#(8+2)xx(13-3)#

#=(10)(10)#

#=100#

Hope this helps :)

Answer 2 · 2017-11-18T07:00:11

#(8+2)xx(13-3)=100#

Simplify:

#(8+2)xx(13-3)#

According to the order of operations, the parentheses are simplified first, and then multiplied.

#10xx10=100#

Answer 3 · 2017-11-18T10:10:39

Solve the brackets
#10xx10#
Solve
#100#