How do you evaluate #8+ 3- 2\div ( 8- 6)#?

1 Answer
Alan P.
Oct 19, 2017

#8+3-2div(8-6)=color(red)(10)#

Explanation:

Using PEDMAS
#8+3-2div(8-6)#

P arentheses first
#= 8+3-2div2#

E xponentiation next
(none here)
#=8+3-2div2#

D ivision and M ultiplication next (left to right)
#=8+3-1#

A ddition and S ubtraction last (left to right)
#=11-1#

#=10#

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