How do you evaluate #[8\cdot 2- ( 3+ 9) ] + [ 8- 2\cdot 3]#?

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Answer 1 · 2017-01-11T07:50:39

#6#

This needs to be calculated using the correct order of operations.

Parentheses first

#[8xx2 - color(red)((3+9))] + [8-2xx3]#

Multiplication and division are done before addition and subtraction.

#=[color(blue)(8xx2) - color(red)(12)] + [8-color(blue)(2xx3)]#

#=[color(blue)(16) - 12] + [8-color(blue)(6)]#

#=" "4" + " "2#

#=6#