Question

How do you evaluate `.85=160/v`?

Answer 1

See a solution process below:

Explanation:

Multiply each side of the equation by `color(red)(v)/color(blue)(0.85)` to solve for `v` while keeping the equation balanced:

`color(red)(v)/cancel(color(blue)(0.85)) xx color(blue)(cancel(color(black)(0.85))) = cancel(color(red)(v))/color(blue)(0.85) xx 160/color(red)(cancel(color(black)(v)))`

`v = 160/0.85`

`v = 160/0.85 xx 100/100`

`v = 16000/85`

`v = (5 xx 3200)/(5 xx 17)`

`v = (color(red)(cancel(color(black)(5))) xx 3200)/(color(red)(cancel(color(black)(5))) xx 17)`

`v = 3200/17`

Or

`v = 188.235` rounded to the nearest thousandth.