How do you simplify #(8r ^ { 2} + 2r + 8) ( 7r + 1)#?

2 Answers
EZ as pi
Jun 4, 2017

#=56r^3 +22r^2 +58r +8#

Explanation:

Get rid of the brackets by multiplying using the distributive law:

#color(red)((8r^2+2r+8))(7r+1)#

#= color(red)(8r^2)(7r+1) + color(red)(2r)(7r+1) +color(red)(8)(7r+1)#

#=56r^3+8r^2 +14r^2+2r +56r +8#

#=56r^3 +22r^2 +58r +8#

Barney V.
Jun 4, 2017

#color(green)(56r^3+22r^2+58r+8#

Explanation:

#(8r^2+2r+8)(7r+1)#

#color(white)(aaaaaaaaaaaaa)##8r^2+2r+8#
#color(white)(aaaaaaaaaa)## xx underline(7r+1)#
#color(white)(aaaaaaaaaaaaa)##56r^3+14r^2+56r#
#color(white)(aaaaaaaaaaaaaaaaaaaa)##8r^2+2r+8#
#color(white)(aaaaaaaaaaaaa)##overline(56r^3+22r^2+58r+8)#

#color(white)(aaaaaaaaaaaaa)##color(green)(56r^3+22r^2+58r+8#

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