# How do you evaluate #(8x - 2) ^ { 2} + 8= - 1#?

##### 1 Answer

Aug 13, 2017

#### Answer:

See below.

#### Explanation:

If imaginary numbers are not accepted (assuming all real numbers), then there are no real solutions to this equation, as the square of a real number is always greater than or equal to zero (since

If we accept imaginary numbers, then we continue as follows: