How do you simplify #(8x - 4) ( 3x - 2) #?

2 Answers
Sep 9, 2017

#24x^2-28x+8#

Explanation:

We start with #(8x-4)(3x-2)#
We will use the FOIL method.

The product of the first terms, #8x# and #3x#, is #24x^2#.

The product of the outside terms, #8x# and #-2#, is #-16x#.

The product of the inside terms, #-4# and #3x#, is #-12x#.

The product of the last terms, #-4# and #-2#, is #8#.

Now we need to sum the products.

#24x^2-16x-12x+8=24x^2-28x+8#

Our answer is #24x^2-28x+8#.

Sep 9, 2017

#24x^2-28x+8#

Explanation:

#"each term in the second factor is multiplied by each"#
#"term in the first factor"#

#(color(red)(8x-4))(3x-2)#

#=(color(red)(8x)xx3x)+(color(red)(8x)xx-2)+(color(red)(-4)xx3x)+(color(red)(-4)xx-2)#

#=24x^2+(-16x)+(-12x)+8#

#=24x^2-16x-12x+8#

#=24x^2-28x+8#