Question

How do you evaluate `(9+ 45) \div 5- 3`?

Answer 1

`7 4/5 =7.8.`

Explanation:

`(9+45)div 5 -3`

Do the sum in the brackets first `(9+45=54)`,

Then divide by `5`

`54/5 = 10 4/5`

Then subtract 3:

`10 4/5 -3=7 4/5`