How do you evaluate #(9x ^ { 2} - 2x - 9) + ( 3x ^ { 2} - 2x + 8)#?

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Answer 1 · 2018-01-30T19:40:09

#(9x^2−2x−9)+(3x^2−2x+8)#

#9x^2−2x−9+3x^2−2x+8#

#12x^2−4x−1#
here, you need to find factors of -12 (-1 x 12) such that their sum equals -4

#12x^2+6x-2x−1#

#6x(2x+1)-1(2x+1)#

#(6x-1)(2x+1)#

-Sahar.