How do you evaluate #a(b^x)# given a=-2, b=3, x=1?

1 Answer
Sep 29, 2017

Answer:

See a solution process below:

Explanation:

Substitute:

  • #color(red)(-2)# for #color(red)(a)#
  • #color(blue)(3)# for color(blue)(b)#
  • #color(green)(1)# for #color(green)(x)#

#color(red)(a)(color(blue)(b)^color(green)(x))# becomes:

#color(red)(-2) xx (color(blue)(3)^color(green)(1)) => color(red)(-2) xx 3 => -6#