# How do you evaluate a(b^x) given a=-3, b=5, x=2?

Apr 18, 2018

$- 75$

#### Explanation:

$a \left({b}^{x}\right)$ is the same as $a \cdot {b}^{x}$.

here, $a = - 3$

$b = 5$ and $x = 2$, so ${b}^{x} = {5}^{2}$

${5}^{2} = 25$

$- 3 \cdot {5}^{2} = - 3 \cdot 25$

$= - 75$