How do you evaluate $a (b^{x})$ $a(b^x)$ given a=5, b=3, x=0?

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How do you evaluate $a (b^{x})$ $a(b^x)$ given a=5, b=3, x=0?

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Answer 1 · 2018-06-02T19:51:36

$5$ $5$

Explanation:

$using the law of exponents$ $"using the "color(blue)"law of exponents"$

$∙ x a^{0} = 1$ $•color(white)(x)a^0=1$

$a (b^{x}) = 5 \times 3^{0} = 5 \times 1 = 5$ $a(b^x)=5xx3^0=5xx1=5$

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How do you evaluate $a (b^{x})$ $a(b^x)$ given a=5, b=3, x=0?

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