How do you evaluate #a(b^x)# given a=5, b=3, x=0?
1 Answer
Jun 2, 2018
Explanation:
#"using the "color(blue)"law of exponents"#
#•color(white)(x)a^0=1#
#a(b^x)=5xx3^0=5xx1=5#
#"using the "color(blue)"law of exponents"#
#•color(white)(x)a^0=1#
#a(b^x)=5xx3^0=5xx1=5#