How do you evaluate #(bc^2+a)/c# given a=12, b=9, c=4?

1 Answer
smendyka
Mar 27, 2018

See a solution process below:

Explanation:

Substitute:

  • #color(red)(12)# for #color(red)(a)#
  • #color(blue)(9)# for #color(blue)(b)#
  • #color(green)(4)# for #color(green)(c)# and evaluate the expression:

#(color(blue)(b)color(green)(c)^2 + color(red)(a))/color(green)(c)# becomes:

#((color(blue)(9) xx color(green)(4)^2) + color(red)(12))/color(green)(4) =>#

#((color(blue)(9) xx color(green)(16)) + color(red)(12))/color(green)(4) =>#

#(144 + color(red)(12))/color(green)(4) =>#

#156/color(green)(4) =>#

#39#

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