Question

How do you evaluate `c=-2c+1/3rs` when s = 3 and c =5?

Answer 1

`r=15`

Explanation:

Substitute the values `s=3,c=5`
`5=-2(5)+1/3*(3)*r`
`5=-10+r`
Shift -10 to the left
`r=5+10`
`r=15`