How do you evaluate #\cot (45^\@ )-\cos (30^\@ )#?

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James Share
May 22, 2018

Answer:

#cot45-cos30=0.134#

Explanation:

show that

#cotx=cosx/sinx#

#cos45=1/sqrt2#

#sin45=1/sqrt2#

#cos30=sqrt3/2#

#cot45-cos30=cos45/sin45-cos30#

#=(1/sqrt2)/(1/sqrt2)-sqrt3/2=1-sqrt3/2=1-0.866=0.134#

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