How do you evaluate #f(x)=2lnx# for #x=0.75#?
With a calculator. And
You can do all sorts of things to this expression, but nothing will get you closer to an answer without using a calculator.
For example, on the right side, you have a rule of logarithms that says you can move that
You can rewrite
So, plug it in your calculator. And if you don't understand what