How do you evaluate #f(x)=4x+1# when #x=-1, x=0,# and #x=3#?

1 Answer
smendyka
Nov 30, 2016

#f(-1) = -3#, #f(0) = 1#, #f(3) = 13#

Explanation:

Substitute the values for #x# into the equation for #x# and solve:

#f(-1) = (4*-1) + 1 = -4 + 1 = -3#

#f(0) = (4*0) + 1 = 0 + 1 = 1#

#f(3) = (4*3) + 1 = 12 + 1 = 13#

Related questions
Impact of this question
4188 views around the world
You can reuse this answer
Creative Commons License