Question

How do you evaluate `f(x)=log_10x` for `x=4/5`?

Answer 1

`f(4/5) ~~ -0.097(3dp)`

Explanation:

`f(x)= log_10x ; x=4/5 :. f(4/5)= log_10(4/5) = log_10 4 -log_10 5`

`~~ 0.602-0.699 ~~ -0.097(3dp)`

`f(4/5) ~~ -0.097(3dp)` [Ans]