How do you evaluate #f(x)=-x^3+8x^2+3# for #f(-7)#?
1 Answer
Jan 25, 2017
Explanation:
To evaluate f(-7), substitute x = - 7 into f(x).
#rArrf(color(red)(-7))=-(color(red)(-7))^3+8(color(red)(-7))^2+3#
#=-(-343)+8(49)+3#
#=343+392+3#
#=738#