How do you evaluate #\frac{1}{3}(2x+8)=\frac{1}{5}(3x-5)#?

Question

655 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-22T05:52:09

#x=-55#

.

#1/3(2x+8)=1/5(3x-5)#

Let's multiply both sides by #15#:

#15/3(2x+8)=15/5(3x-5)#

#5(2x+8)=3(3x-5)#

#10x+40=9x-15#

#10x-9x=-15-40#

#x=-55#