How do you evaluate #\frac { 2} { 3} \times ( - \frac { 1} { 3} ) \div ( - \frac { 1} { 2} )#?

2 Answers
Dec 27, 2016

Since there are an even number of #-#'s in the multiplication and division, they cancel out two by two.

Explanation:

#=2/3xx1/3div1/2#

You may change the division by multiplication with the inverse (=fraction upside down):

#=2/3xx1/3xx2/1#

#=(2xx1xx2)/(3xx3xx1)=4/9#

Dec 29, 2016

#4/9#

Explanation:

When you multiplying or dividing 2 values, if the signs are the same the answer is positive (plus). If they are not the same then answer is negative (minus).

Consider the part that reads: #(-1/3)-:(1/2)#

We are dividing and the signs are the same so the answer for this bit is positive.

So #(-1/3)-:(-1/2)# gives the same answer as #1/3-:1/2#

Using the shortcut method, turn #1/2# upside down and multiply

So #2/3xx(-1/3)-:(-1/2)# becomes:

#" "2/3" "xx" "1/3" "xx" "2/1" " =" "(2xx1xx2)/(3xx3xx1)" " =" " 4/9#