How do you evaluate 2(x2+32)(x+8)(x8)x4x+8?

2 Answers
Feb 1, 2017

x+4x8

Explanation:

Take out 1x+8 as a common factor

1x+8[2(x2+32)x8(x4)]

1x+8[2(x2+32)(x4)(x8)x8]

1x+8[2x2+64x2+12x32x8]

x2+12x+32(x+8)(x8)

Now factorise the numerator

(x+8)(x+4)(x+8)(x8)

x+4x8

Feb 1, 2017

=x+4x8

Explanation:

2(x2+32)(x+8)(x8)x4x+8

=2(x2+32)(x4)(x8)(x+8)(x8)

=2(x2+32)(x28x4x+32)(x+8)(x8)

=2x2+64x2+12x32(x+8)(x8)

=x2+12x+32(x+8)(x8)

=x2+8x+4x+32(x+8)(x8)

=x(x+8)+4(x+8)(x+8)(x8)

=(x+8)(x+4)(x+8)(x8)

=x+4x8