How do you evaluate #(- \frac { 3} { 4} ) ( - 12x ) ( - 1) #?

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Answer 1 · 2017-11-11T11:29:24

See a solution process below:

First rewrite the expression as:

#(-3/4 xx -12)(-1)(x) =>#

#(-3/4 xx (-3 xx 4))(-1)(x) =>#

#(-3/(color(red)(cancel(color(black)(4)))1) xx (-3 xx color(red)(cancel(color(black)(4)))1))(-1)(x) =>#

#(-3/1 xx (-3 xx 1))(-1)(x) =>#

#(-3 xx -3)(-1)(x) =>#

#(9)(-1)(x) =>#

#(9 xx -1)(x) =>#

#(-9)(x) =>#

#-9x#