How do you evaluate #-\frac { 3} { 4} m + 15# and #m = 12#?

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Answer 1 · 2017-08-07T01:53:06

See a solution process below:

Substitute #color(red)(12)# for #color(red)(m)# in the expression and calculate the result:

#-3/4color(red)(m) + 15# becomes:

#(-3/4 xx color(red)(12)) + 15#

#(-3/color(red)(cancel(color(black)(4))) xx cancel(color(red)(12))color(red)(3)) + 15#

#(-3 xx color(red)(3)) + 15#

#-9 + 15#

#6#