How do you evaluate #\frac { 3} { v + 1} + \frac { 7} { 5v }#?

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Answer 1 · 2017-08-29T13:44:50

#=(22v+7)/(5v(v+1))#

The expression can't be 'evaluated' because there is no value given for the variable, so I assume you mean 'simplify',?

To add the two fractions you need a common denominator.
In this case it will be #5v(v+1)#

Multiply each fraction by #color(blue)(1)# to create an equivalent fraction.

#3/(v+1) color(blue)(xx (5v)/(5v)) + 7/(5v) color(blue)(xx (v+1)/(v+1))#

#=(15v)/(5v(v+1)) + 7/(5v(v+1))#

#= (15v + 7(v+1))/(5v(v+1))#

#=(15v+7v+7)/(5v(v+1))#

#=(22v+7)/(5v(v+1))#