How do you evaluate #\frac{36}{1}\times \frac{1}{2}#?

2 Answers
MeneerNask
Dec 12, 2016

#A/BxxC/D=(AxxC)/(BxxD)#

Explanation:

#=(36xx1)/(1xx2)=36/2=18#

Tony B
Dec 14, 2016

18

Explanation:

#color(purple)("With practice you will start to do a lot of this in your head and not") ##color(purple)("need to write down as many steps as I have.")#

Consider the method example of #2xx4" is the same as "4xx2#

Using this principle we have:

#color(green)(36/1xxcolor(red)(1/2)" "=" "(36xxcolor(red)(1))/(1xxcolor(red)(2)) " "=" "(36xxcolor(red)(1))/(color(red)(2)xx1))" "=" "36/2xx1/1#

# = 36/2xx1=36/2#

Divide top and bottom by 2

#=(36-:2)/(2-:2) = 18/1=18#

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